Question

Simplify the following expressions and evaulate them as directed:

i) x²(3-2x+x²) for x=1; x=-1 ; x=⅔ and x= -½


plz tell full explanation mummy ​

Answer 1

Answer:

x = 1) x^1 ( 3 - 2*1 + x^1)

        x ( 1 + x )

        $x + x^{2}$

x = -1) x^(-1) [ 3 - 2*(-1) + x^(-1) ]

         1/x [ 3 - (-2) + 1/x ]

         1/x ( 3 + 2 + 1/x )

         1/x ( 5 + 1/x )

         $\frac{5}{x} + \frac{1}{x^{2} }$

x = 3/4) x^(2/3) [ 3 - 2*(2/3) + x^(2/3)]

            $\sqrt[3]{x^{2} }$ [ 3 - 4/3 + $\sqrt[3]{x^{2} }$ ]

            $\sqrt[3]{x^{2} }$ [ (9/3 - 4/3) + $\sqrt[3]{x^{2} }$ ]

            $\sqrt[3]{x^{2} }$ [ 5/3 + $\sqrt[3]{x^{2} }$ ]

             $\frac{5}{3} \sqrt[3]{x^{2} }$ + $\sqrt[3]{x^{4} }$

x = -1/2) x^(-1/2) [ 3 - 2*(-1/2) + x^(-1/2)]

             $\frac{1}{\sqrt{x} }$ [ 3 - (-1) + $\frac{1}{\sqrt{x} }$ ]

             $\frac{1}{\sqrt{x} }$ [ 3 + 1 + $\frac{1}{\sqrt{x} }$ ]

             $\frac{1}{\sqrt{x} }$ ( 4 + $\frac{1}{\sqrt{x} }$ )

             $4 \frac{1}{\sqrt{x} } + \frac{1}{x}$

   HOPE IT HELPS!!! :D