Simplify the following:
(i) a² (b² – c²) + b2 (c² – a²) + c² (a² – b²)
(ii) x²(x – 3y²) – xy(y² – 2xy) – x(y³ – 5x²)
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⠀⠀ıllıllı uoᴉʇnloS ıllıllı
(i) a² (b² - c²) + b² (c² - a²) + c² (a² - b²)
= (a²b² - a²c²) + (b²c² - b²a²) + (c²a² - c²b²)
= 0
(ii) x²(x - 3y²) - xy(y² - 2xy) - x(y³ - 5x²)
= x³ - 3x²y² - xy³ + 2x²y² - xy³ + 5x³
= x³ + 5x3 - 3x²y² + 2x²y² - xy³ - xy³
= 6x³ - x²y² - 2xy³
Additional Information:
- A combination of numbers, literal numbers and fundamental operations is called an algebraic expression.
- Parts of an algebraic expression separated by the symbols ( + ) and ( - ) are called the terms of the algebraic expression.
Answered by
0
Answer:
(I) a²b²-a²c²+b²c²-b²a²+c²a²-c²b²
=a²b²-b²a²+c²a²-a²c²+b²c²-c²b²
=0
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