Math, asked by mukeshkumar8196, 10 months ago

Simplify the following:
(i) a² (b² – c²) + b2 (c² – a²) + c² (a² – b²)
(ii) x²(x – 3y²) – xy(y² – 2xy) – x(y³ – 5x²)​

Answers

Answered by Anonymous
18

⠀⠀ıllıllı uoᴉʇnloS ıllıllı

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(i) a² (b² - c²) + b² (c² - a²) + c² (a² - b²)

= (a²b² - a²c²) + (b²c² - b²a²) + (c²a² - c²b²)

= 0

(ii) (x - 3y²) - xy( - 2xy) - x( - 5x²)

= x³ - 3x²y² - xy³ + 2x²y² - xy³ + 5x³

= x³ + 5x3 - 3x²y² + 2x²y² - xy³ - xy³

= 6x³ - x²y² - 2xy³

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Additional Information:

  • A combination of numbers, literal numbers and fundamental operations is called an algebraic expression.
  • Parts of an algebraic expression separated by the symbols ( + ) and ( - ) are called the terms of the algebraic expression.

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Answered by priyarajbhar542
0

Answer:

(I) a²b²-a²c²+b²c²-b²a²+c²a²-c²b²

=a²b²-b²a²+c²a²-a²c²+b²c²-c²b²

=0

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