Question

Simplify the following: (i) [x2 - 4x - 1 - (2x2 – 5x - 2)] - (6x2 – 2x + 1)​

Answer 1

Question :-

$\green\succ$Simplify the following:

(i) $\footnotesize\tt{ [{x}^{2} - 4x - 1 - ( {2x}^{2} - 5x - 2)]-({6x}^{2}-2x+1)}$

Solution :-

$\red\mapsto\footnotesize\sf{{x}^{2} - 4x - 1 - {2x}^{2} + 5x + 2 - {6x}^{2} + 2x - 1}$

$\red\mapsto\footnotesize\sf{{x}^{2} -{2x}^{2} + {6x}^{2} -4x + 5x + 2x - 1 + 2 - 1 }$

$\red\mapsto\footnotesize\sf\boxed{{5x}^{2} - 3x}$

More to know:-

• (+) + (+) = +
• (-) + (-) = +
• (+) + (-) = +
• (+) + (-) = -

Hope it helps :)

Answer 2

Answer:

Question :-

$\green\succ≻$ Simplify the following:

(i) $\footnotesize\tt{ [{x}^{2} - 4x - 1 - ( {2x}^{2} - 5x - 2)]-({6x}^{2}-2x+1)}[x </p><p>2</p><p> −4x−1−(2x </p><p>2</p><p> −5x−2)]−(6x </p><p>2</p><p> −2x+1)$

Solution :-

$\red\mapsto\footnotesize\sf{{x}^{2} - 4x - 1 - {2x}^{2} + 5x + 2 - {6x}^{2} + 2x - 1}↦x </p><p>2</p><p> −4x−1−2x </p><p>2</p><p> +5x+2−6x </p><p>2</p><p> +2x−1$

$\red\mapsto\footnotesize\sf{{x}^{2} -{2x}^{2} + {6x}^{2} -4x + 5x + 2x - 1 + 2 - 1 }↦x </p><p>2</p><p> −2x </p><p>2</p><p> +6x </p><p>2</p><p> −4x+5x+2x−1+2−1$

$\red\mapsto\footnotesize\sf\boxed{{5x}^{2} - 3x}↦ </p><p>5x </p><p>2</p><p> −3x$