Simplify the following mathematical expressions using BODMAS.
a. 83-[29-{6÷3-(6-9÷3)÷3}]
b.[87-12÷3 of 4]+(37-29)×4
c.500-[80+{20-(60-50)}]
d.(-21)÷[16+(-13)]+(-5)
please write full formula
Answers
Answered by
48
a)83-[29-{6÷3-(6-9÷3)÷3}]
83-[29-{6÷3-(6-3)÷3}]
83-[29-{6÷3-(3)÷3}]
83-[29-{3-3÷3}]
83-[29-{3-1}]
83-[29-2]
83-27
56
b)[87-12÷3 of 4]+(37-29)×4
[87-12÷12]+8×4
[87-1]+32
86+32
118
83-[29-{6÷3-(6-3)÷3}]
83-[29-{6÷3-(3)÷3}]
83-[29-{3-3÷3}]
83-[29-{3-1}]
83-[29-2]
83-27
56
b)[87-12÷3 of 4]+(37-29)×4
[87-12÷12]+8×4
[87-1]+32
86+32
118
prithvisinghclass6:
and also write c,d answer
Answered by
0
Concept
According to the rules of BODMAS, while solving an expression, brackets must be solved first, followed by division, multiplication, addition and lastly subtraction of terms.
Find
a. 83-[29-{6÷3-(6-9÷3)÷3}]
b.[87-12÷3 of 4]+(37-29)×4
c.500-[80+{20-(60-50)}]
d.(-21)÷[16+(-13)]+(-5)
Solution
a. 83-[29-{6÷3-(6-9÷3)÷3}]
= 83-[29-{2-(6-3)÷3}]
= 83-[29-{2-(3)÷3}]
= 83-[29-{2-1}]
= 83-[29-{1}]
= 83-[28]
= 55
b. [87-12÷3 of 4]+(37-29)×4
= [87- 4 of 4] + (8)×4
= [87- 16] + (8)×4
= 71 + 32
= 103
c. 500-[80+{20-(60-50)}]
= 500-[80+{20-(10)}]
= 500-[80+{10}]
= 500-[90]
= 410
d. (-21)÷[16+(-13)]+(-5)
= (-21)÷[3]+(-5)
= -7+(-5)
= -12
Thus, the answers to the given question are a. 55, b. 103, c. 410, d. -12
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