Math, asked by prithvisinghclass6, 1 year ago

Simplify the following mathematical expressions using BODMAS.
a. 83-[29-{6÷3-(6-9÷3)÷3}]
b.[87-12÷3 of 4]+(37-29)×4
c.500-[80+{20-(60-50)}]
d.(-21)÷[16+(-13)]+(-5)
please write full formula

Answers

Answered by sinisrinath
48
a)83-[29-{6÷3-(6-9÷3)÷3}]
83-[29-{6÷3-(6-3)÷3}]
83-[29-{6÷3-(3)÷3}]
83-[29-{3-3÷3}]
83-[29-{3-1}]
83-[29-2]
83-27
56

b)[87-12÷3 of 4]+(37-29)×4
[87-12÷12]+8×4
[87-1]+32
86+32
118

prithvisinghclass6: and also write c,d answer
Answered by aditijaink283
0

Concept

According to the rules of BODMAS, while solving an expression, brackets must be solved first, followed by division, multiplication, addition and lastly subtraction of terms.

Find

a. 83-[29-{6÷3-(6-9÷3)÷3}]

b.[87-12÷3 of 4]+(37-29)×4

c.500-[80+{20-(60-50)}]

d.(-21)÷[16+(-13)]+(-5)

Solution

a. 83-[29-{6÷3-(6-9÷3)÷3}]

= 83-[29-{2-(6-3)÷3}]

= 83-[29-{2-(3)÷3}]

= 83-[29-{2-1}]

= 83-[29-{1}]

= 83-[28]

= 55

b. [87-12÷3 of 4]+(37-29)×4

= [87- 4 of 4] + (8)×4

= [87- 16] + (8)×4

= 71 + 32

= 103

c. 500-[80+{20-(60-50)}]

= 500-[80+{20-(10)}]

= 500-[80+{10}]

= 500-[90]

= 410

d. (-21)÷[16+(-13)]+(-5)

= (-21)÷[3]+(-5)

= -7+(-5)

= -12

Thus, the answers to the given question are a. 55, b. 103, c. 410, d. -12

#SPJ3

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