Question

simplify the following numerical expressions a.32-45÷5+3 b. 2880÷48+160-200 128-4×21÷3+1250 c. 950-125×0+625÷25-5×5​

Answer 1

${[A]} \: 32 - 45 \div 5 + 3$

$= 32 - 9 + 3$

$= 26$

$[B] \: 2880 \div 48 + 160 - 200$

$= 60 + 160 - 200$

$= 20$

$[C] \: 128-4 \times 21 \div 3+1250$

$= 128 - 4 \times 7 + 1250$

$= 1350$