simplify the following question . solve only vii part of question 4
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Step-by-step explanation:
[(2/3)^2]^3 × (1/3)^-1 × 3^-1 × 1/6
= (2/3)^6 × 3^1×3^-1 × 1/6
= (2/3)^6 × 3^1+(-1) × 1/6
= (2/3)^6 × 3^0 × 1/6
= 64/729 × 1 × 1/6
= 32/729× 1/3
= 32/2187
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