Math, asked by kushwahapihu3762, 3 months ago

Simplify the following statements:
~(~p^q)

Answers

Answered by mathdude500
9

\large\underline{\sf{Solution-}}

\rm :\longmapsto\: \sim( \sim \: p \:  \land \: q)

We know,

\boxed{ \tt{ \:  \sim (\sim \: p) \:  =  \: p \: }}

So,

\red{\bf\implies \:\boxed{ \tt{ \:\: \sim( \sim \: p \:  \land \: q) \:   =  \: p \:  \lor \:  \sim \: q}}}

Justification :-

Consider,

\rm :\longmapsto\: \sim( \sim \: p \:  \land \: q)

Truth table are as follow :-

\begin{gathered}\boxed{\begin{array}{c|c|c|c|c} \bf p & \bf q& \bf  \sim \: p& \bf  \sim p\:  \land \: q& \bf   \sim( \sim \: p \land \: q)\\ \frac{\qquad}{} & \frac{\qquad}{}& \frac{\qquad}{} & \frac{\qquad}{}& \frac{\qquad}{}\\ \sf T & \sf T & \sf F& \sf F& \sf T\\ \\\sf T & \sf F & \sf F& \sf F& \sf T\\ \\\sf F & \sf T & \sf T& \sf T& \sf F\\ \\\sf F & \sf F & \sf T& \sf F& \sf T  \end{array}} \\ \end{gathered}

Now, Consider

\rm :\longmapsto\:p \:  \lor \:  \sim \: q

Truth table are as follow :-

\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf p & \bf q& \bf  \sim \: q& \bf  p \:  \lor \: \sim q\\ \frac{\qquad}{} & \frac{\qquad}{}& \frac{\qquad}{} & \frac{\qquad}{}\\ \sf T & \sf T & \sf F& \sf T\\ \\\sf T & \sf F & \sf T& \sf T\\ \\\sf F & \sf T & \sf F& \sf F\\ \\\sf F & \sf F & \sf T& \sf T  \end{array}} \\ \end{gathered}

Hence,

\red{\bf\implies \:\boxed{ \tt{ \:\: \sim( \sim \: p \:  \land \: q) \:   =  \: p \:  \lor \:  \sim \: q}}}

Additional Information :-

\begin{gathered}\boxed{\begin{array}{c|c|c|c|c} \bf p & \bf q& \bf p \: \lor \: q& \bf q  \:  \land \: p& \bf  p \:  \to \: q\\ \frac{\qquad}{} & \frac{\qquad}{}& \frac{\qquad}{} & \frac{\qquad}{}& \frac{\qquad}{}\\ \sf T & \sf T & \sf T& \sf T& \sf T\\ \\\sf T & \sf F & \sf T& \sf F& \sf F\\ \\\sf F & \sf T & \sf T& \sf F& \sf T\\ \\\sf F & \sf F & \sf F& \sf F& \sf T  \end{array}} \\ \end{gathered}

Answered by shivasinghmohan629
0

Step-by-step explanation:

Since columns corresponding to ¬(p∨q) and (¬p∧¬q) match, the propositions are logically equivalent. ... Since columns corresponding to p∨(q∧r) and (p∨q)∧(p∨r) match, the propositions are logically equivalent. This particular equivalence is known as the Distributive Law.

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