Question

Simplify the following, using 2nd law, $a^{m} \div a^{n}=a^{m-n} : (-3)^5 \div (-3)^2$

Answer 1

Solutions :-


In this question we have to use $a^{m} \div a^{n}=a^{m-n}$

$Q: \: (-3)^5 \div (-3)^2 \\ \\ = > ( - 3)^{5 - 2} \\ \\ = > {( - 3)}^{3}$



Hence,
(-3)³ or - 27 is the required answer.

Answer 2

Answer :

The second law is -

${a}^{m} \div {a}^{n} = {a}^{m - n}$

Given :

${( - 3)}^{5} \div {( - 3)}^{2}$

Using second law -

When the base is same, we should subtract the powers.

Here, base is ( - 3 )

The powers are 5 and 2.

${( - 3)}^{5} \div {( - 3)}^{2}$

${( - 3)}^{5 - 2}$

${( - 3)}^{3}$

We read it as "minus three cube" or "minus three to the power of three.


${( - 3)}^{3} = 27$

Hence : Required Answer is 27.