Math, asked by StarTbia, 1 year ago

Simplify the following, using 2nd law, a^{m} \div a^{n}=a^{m-n} : x^{11} \div x^3

Answers

Answered by Anonymous
18
x¹¹ ÷ x³
x¹¹-³
 {x}^{8}
Answered by sk98764189
0

Answer:

x^{8}

Step-by-step explanation:

According to the question

We have to use the 2nd law.

a^{m}\div a^{n} = a^{m\ -\ n}

The given expression is

x^{11}\div x^{3}

= x^{11\ -\ 3} (According to the 2nd law)

= x^{8} (Answer)

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