Hindi, asked by pranitha1473, 11 months ago

Simplify the following using multiplication and division properties of surds root 225/729 - root 25/144 ÷ root 16 / 81

Answers

Answered by santy2
6

Answer:

Simplify the following using multiplication and division properties of surds:

\sqrt\frac{225}{729} - \sqrt\frac{25}{144} ÷ \sqrt\frac{16}{81}

= \frac{-55}{144}

Explanation:

To solve the following equation by use of the multiplication and division of surds, we will use the second property of surds:

\sqrt\frac{225}{729} - \sqrt\frac{25}{144} ÷ \sqrt\frac{16}{81}

Second multiplication property of surds:

\sqrt\frac{a}{b}  can be written as or = \frac{\sqrt{a} }{\sqrt{b} }

Therefore:

\sqrt\frac{225}{729} - \sqrt\frac{25}{144} ÷ \sqrt\frac{16}{81}   =  \frac{\sqrt{225} }{\sqrt{729} } - \frac{\sqrt{25} }{\sqrt{144} } ÷ \frac{\sqrt{16} }{\sqrt{81} }

= \frac{15}{27} - \frac{5}{12} ÷ \frac{4}{9}

At this point, you will use PEMDAS/BODMAS to solve equation.

First start with the divison then subtraction:

Division

\frac{15}{27} - \frac{5}{12} ÷ \frac{4}{9}

\frac{15}{27} - \frac{5}{12} ÷ \frac{4}{9}

\frac{5}{12} ÷ \frac{4}{9} = \frac{5}{12} × \frac{9}{4}  = \frac{15}{16}

Subtraction:

\frac{15}{27} - \frac{15}{16}

= \frac{240 - 405}{432}

= \frac{-165}{432}

= \frac{-55}{144}

The solution to this thus = \frac{-55}{144}

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