Question

Simplify the function to a minimum number of literal using Boolean algebra.
F = XY'Z + X'Y'Z + W'XY + WX'Y + WXY​

Answer 1

Explanation:

char op; float num1, num2; cout << "Enter operator: +, -, *, /: "; cin >> op; cout << "Enter two operands: "; cin >> num1 >> num2; switch(op) { case '+': cout << num1 << " + " << num2 << " = " << num1 + num2; break; case '-': cout << num1 << " - " << num2 << " = " << num1 - num2; break; case '*': cout << num1 << " * " << num2 << " = " << num1 * num2; break; case '/': cout << num1 << " / " << num2 << " = " << num1 / num2; break; default: // If the operator is other than +, -, * or /, error message is shown cout << "Error! operator is not correct"; break; } return 0; }

Output

Enter operator either + or - or * or divide : - Enter two operands: 3.4 8.4 3.4 - 8.4 = -5.0

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