Question

simplify the given algebraic rational expression​

Answer 1

Answer:

$\frac{4x^2}{x^4-1}$ is the simplified form of $\frac{1}{x-1}-\frac{1}{x+1}+\ \frac{2}{x^2+1}$(PROVEN BELOW)

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Step-by-step explanation:

$\frac{1}{x-1}-\frac{1}{x+1}+\ \frac{2}{x^2+1}$

$=\frac{\left(x^3+x^2+x+1-x^3+x^2-x+1+2x^2-2\right)}{x^4-1}$

$=\frac{4x^2}{x^4-1}$