simplify the logic function.
f=A'BCD + AB'CD + A'B'C'D'+ A'B'C'D'
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Answer:
Explanation:
a. F (A,B,C) = A’ B’ C’ + A’ B’ C + A B’ C’ + A B’ C + A B C’ + A B C
[Distributive]
= A’B’ (C’ + C) + AB’ (C’ + C) + AB (C’ + C) [ Complementarity]
= A’B’ + AB’ + AB [Idempotency]
= A’B’ + AB’ + AB’ +AB [ Distributive]
= B’ (A’ + A) + A (B’ + B) [ Complementarity]
= B’ + A
b. F(A,B) = (A’+B) ( A+B) [Distributive]
= AA’ + A’B+ AB+ BB [Complementarity ]
= A’B+AB+BB [Distributive]
= B ( A’+A+1) [Complementarity]
= B . 1 [ identity ]
= B
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