Question

Simplify the question :13/26*1/2(7/2-1/8+3/6*6/3-18)

Answer 1

Answer:

Answer is attached here

Answer 2

To solve : $\frac{13}{26} \times \frac{1}{2}(\frac{7}{2} - \frac{1}{8}+ \frac{3}{6} \times \frac{6}{3} -18 )$

Solution:-

• To solve the above equation we will follow BODMAS rule.

• It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

• where,  

                   $\begin{array}{l} \\B=brackets\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { Division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

• According to above rule we will solve.
• $\frac{13}{26} \times \frac{1}{2}(\frac{7}{2} - \frac{1}{8}+ \frac{3}{6} \times \frac{6}{3} -18 )$  

       $= \frac{13}{52} ( \frac{7}{2} -\frac{1}{8} + 1 - 18 ) \\= \frac{13}{52 } (\frac{28-1+8 - 144}{8} ) \\= \frac{13}{52} \times \frac{-109}{8} \\= \frac{1}{4}\times \frac{-109}{8} \\= \frac{-109}{32}$

Hence , value of $\frac{13}{26} \times \frac{1}{2}(\frac{7}{2} - \frac{1}{8}+ \frac{3}{6} \times \frac{6}{3} -18 )$ is $\frac{-109}{32}$ .