Question

simplify the question​ in the attachment​

Answer 1

Answer:

I don't know the answer of this equations because this chapter is not done in my school now ..So that I will not want to explain this sum

Answer 2

Answer:

 1

Step-by-step explanation:

$[\frac{x^(a^2)^-^b}{x^c^(a-b)} ]*\frac{x^(b^2-c^2)}{x^a(b-c)} *\frac{x^(c^2-a^2}{x^b(c-a)}$

now simplify the equation by adding and subtracting the powers respectively .

$\frac{x^(a^2-b^2+b^2-c^2+c^2-a^2)}{x^(ac-bc+ab-ac+bc-ab)}$

now obviously all the powers cancel each other.

$\frac{x^0}{x^0} =\frac{1}{1}$

answer is therefore.

1

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hope it helped :-)