Math, asked by david91, 1 year ago

simplify the question please
solve it right now

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Answered by sangramsingh1208
1
6a^3-12ab-ab^2-4ab =6a^3-16ab-ab^2
Answered by Anonymous
12

2 {a}(3 {a}^{2}  - 6b) -  \frac{1}{2} b(2ab + 8a) \\  \\ multiply \: 2a \: with \: bracket \\  \\ 2a \times 3 {a}^{2}  - 2a \times 6b -  \frac{1}{2} b(2ab + 8a) \\  \\ 6 {a}^{3}  - 12ab -  \frac{1}{2} b(2ab + 8a) \\  \\ factor \: out \: 2 \: from \: (2ab + 8a) \\  \\  {6a}^{3}  - 12ab -  \frac{1}{2} b \times 2(ab + 4a)


reduce \: the \: fraction \\  \\  {6a}^{3}  - 12ab - b(ab + 4a) \\  \\ mutliply \:  - b \: with \: (ab + 4a) \\  \\  {6a}^{3}  - 12ab -  {ab}^{2}   -  4ab \\  \\ collect \: like \: terms \\  \\  {6a}^{3}  - 16ab -  {ab}^{2}
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