Simplify the square root of (1-cos theta)\(1+cos theta)
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For this problem, we can use the difference of squares methods, which tells us that
(a−b)(a+b)=a2−b2
Applying this method, we then get
√(1−cosθ)(1+cosθ)=√1−cos2θ
Also note that sin2θ+cos2θ=1→sin2θ=1−cos2θ
Thus we can simplify this even further, giving us
√1−cos2θ=√sin2θ
We have to be careful here, because the root implies that we should have to answers. In fact, if we would have made the mistake of saying that √sin2θ=sinx
(a−b)(a+b)=a2−b2
Applying this method, we then get
√(1−cosθ)(1+cosθ)=√1−cos2θ
Also note that sin2θ+cos2θ=1→sin2θ=1−cos2θ
Thus we can simplify this even further, giving us
√1−cos2θ=√sin2θ
We have to be careful here, because the root implies that we should have to answers. In fact, if we would have made the mistake of saying that √sin2θ=sinx
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