Math, asked by debjanimunshi370, 1 day ago

simplify the sum .
useless answers will be reported.
please help me friends fast !​

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Answered by Somin
1

Answer:

x ^{2} y {3} z \times 7 {x}^{3 {y}^{ - 3} }  {z}^{2 \times ( -   \frac{1}{8}  {x}^{2} } {y}^{8} ) \\ 7 {x}^{2 + 3}   {y}^{3 - 3}  {z}^{1 + 2}  \times -   \frac{1}{8} {x}^{2}  {y}^{8}  \\  - \frac{7}{8}  {x}^{5 + 2}  {y}^{0 + 8}  {z}^{3}  \\  -  \frac{7}{8}  {x}^{7}  {y}^{8}  {z}^{3}

here is your answer

Answered by rawatnikki2003
0

Answer:

</p><p>y3z×7x3y−3z2×(−81x2y8)7x2+3y3−3z1+2×−81x2y8−87x5+2y0+8z3−87x7y8z3</p><p></p><p></p><p>

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