simplify, then find(x, y)= (7x+iy)(2-i) =5(2-3i)+2(1+2i)
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x = 1
y = -2
Step-by-step explanation:
(7x + iy)(2 - i) = 5(2 - 3i) + 2(1 + 2i)
14x - 7xi + 2yi - yi² = 10 - 15i + 2 + 4i
14x- 7xi + 2yi + y = - 11i + 12
7xi - 2yi - 11i = 14x + y - 12
(7x - 2y - 11)i = (14x + y - 12)
(7x - 2y - 11)i + (-14x - y + 12) = 0
Real no. = (-14x - y + 12) × 2 = 0 -------- (i)
Imaginary no. = (7x - 2y - 11) = 0 -------- (ii)
(-28x - 2y + 24) = 0 -------- (iii)
(-28x - 2y + 24) - (7x - 2y - 11) = 0
-28x - 2y + 24 - 7x + 2y + 11 = 0
-35x + 35 = 0
x = 35/35
x = 1
(-28x - 2y + 24) = 0
-28(1) - 2y + 24 = 0
-4 - 2y = 0
2y = -4
y = -4/2
y = -2
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