Simplify this √(1+sinA) /(1-sinA)
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L.H.S.=√1+sinA/1-sinA
=√(1+sinA)(1+sinA)/(1-sinA)(1+sinA)
=√(1+sinA)^/1-sin^A
=√(1+sinA)^/cos^A
=1+sinA/cosA
= 1/cosA+ sinA/cosA
=secA+tanA
=R.H.S. prove
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