Question

simplify this............​

Answer 1

Step-by-step explanation:

2^15×7^3/ 2^9×7

8=2^3 ; 8^3=( 2^3)^3=2^9

2^15-9 × 7^3-1

2^6 × 7^2

64 × 49

3136

Answer 2

$\tt\huge \underline{\underline{ANSWER}}$

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$\sf \LARGE :\implies\frac{(2 {}^{5}) {}^{3} \times 7 {}^{3} }{ {8}^{3} \times 7 }$

$\sf \LARGE : \implies\frac{2 {}^{15} \times 7 {}^{3} }{ {(2 {}^{3} )}^{3} \times 7 }$

$\sf \LARGE : \implies\frac{2 {}^{15} \times 7 {}^{3} }{ {2}^{9} \times 7 }$

$\sf \LARGE : \implies2 {}^{15 - 9} \times 7 {}^{3 - 1}$

$\sf \LARGE : \implies \: 64 \times 49$

$\LARGE \boxed{\purple{\sf: \implies 3136}}$

Power of exponents:

$\begin{gathered}\boxed{\begin{minipage}{5 cm}\bf{\dag}\:\:\underline{\text{Law of Exponents :}}\\\\\bigstar\:\:\sf\dfrac{a^m}{a^n} = a^{m - n}\\\\\bigstar\:\:\sf{(a^m)^n = a^{mn}}\\\\\bigstar\:\:\sf(a^m)(a^n) = a^{m + n}\\\\\bigstar\:\:\sf\dfrac{1}{a^n} = a^{-n}\\\\\bigstar\:\:\sf\sqrt[\sf n]{\sf a} = (a)^{\dfrac{1}{n}}\end{minipage}}\end{gathered}$

NOTE-Kindly see this answer on web to see rules of exponents.