Question

simplify this and become the brainliest

Answer 1

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Answer 2

$= \ \textgreater \ Given : \frac{9 * 2^n + 3 * 2^{n - 1} }{ 2^{n + 1} - 2^{n - 1} }$


$= \ \textgreater \ \frac{3 * 3 * 2^n + 3 * 2^n * 2^{-1} }{ 2^n * 2 - 2^n * 2^{-1} }$

$= \ \textgreater \ \frac{3( 2^{-1} + 3) * 2^n }{ 2^{-1}(4 - 1) * 2^n }$

$= \ \textgreater \ \frac{3( \frac{1}{2} + 3) * 2^n }{3 * 2^{n - 1} }$

$= \ \textgreater \ 2( \frac{1}{2} + 3)$

$= \ \textgreater \ 2( \frac{7}{2} )$

= > 7.



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