Question

Simplify this, (exponents)​

Answer 1

$\frac{ {2}^{n + 1} + {2}^{n} }{ {2}^{n + 3} - {2}^{n} } = \frac{ {2}^{n} \times {2}^{1} + {2}^{n} }{ {2}^{n} \times {2}^{3} - {2}^{n} } \\ = \frac{2 \times {2}^{n} + {2}^{n} }{8 \times {2}^{n} - {2}^{n} } \\ = \frac{ {2}^{n}(2 + 1) }{ {2}^{n}(8 - 1) } \\ = \frac{3}{7}$

Hope it is helpful.