Question

simplify this

please help me​

Answer 1

We need to apply BODMAS to solve the given questions.

BODMAS is an operation which tells us in which order a problem should be solved.

BODMAS is an acronym for brackets, of, division, multiplication, addition and subtraction.

(i) $\sf 19+12\div 6-2\times 3$

Here we need to do division first then multiplication then addition and at last subtraction.

⇒ $\sf 19+12\div 6-2\times 3$

⇒ $\sf 19+2-2\times 3$

⇒ $\sf 19+2-6$

⇒ $\sf 21-6$

⇒ $\sf 15$

∴ $\sf 19+12\div 6-2\times 3=15$

(ii) $\sf 23+18\div 6 +3\times (-4)$

Here we need to do division first then multiplication then addition and at last subtraction.

⇒ $\sf 23+3 +3\times (-4)$

⇒ $\sf 23+3+-12$

⇒ $\sf 23+3-12$

⇒ $\sf 26-12$

⇒ $\sf 14$

∴$\sf 23+18\div 6 +3\times (-4)=14$

(iii) $\sf 9-\{5\times 3 +12\times16\div(-8)\}$

Here we need to do brackets (in the brackets we do division first, then multiplication and finally addition) and at last subtraction.

⇒ $\sf 9-\{5\times 3 +12\times16\div(-8)\}$

⇒ $\sf 9-\{5\times 3 +12\times-2\}$

⇒ $\sf 9-\{15+-24\}$

⇒ $\sf 9-\{ 15-24\}$

⇒ $\sf 9-(-9)$

⇒ $\sf 18$

∴$\sf 9-\{5\times 3 +12\times16\div(-8)\}=18$

(iv) $\sf 12-[13-\{9+10\div(7-2)\}]$

Here we need to do simple bracket (in the simple bracket we do subtraction) first then curly brackets (in the curly brackets we do the division first and then addition) and then box bracket (We do subtraction in the box bracket) and at last subtraction.

⇒ $\sf 12-[13-\{9+10\div(7-2)\}]$

⇒ $\sf 12-[13-\{9+10\div5\}]$

⇒ $\sf 12-[13-\{9+2\}]$

⇒ $\sf 12-[13-11]$

⇒ $\sf 12-2$

⇒ $\sf 10$

∴ $\sf 12-[13-\{9+10\div(7-2)\}]=10$

(v) $\sf 28-[15-\{8+20\div(7-(8-6))\}]$

Here we need to do simple bracket first then curly brackets the box brackets and finally subtraction.

⇒ $\sf 28-[15-\{8+20\div(7-(8-6))\}]$

⇒ $\sf 28-[15-\{8+20\div(7-2)\}]$

⇒ $\sf 28-[15-\{8+20\div5\}]$

⇒ $\sf 28-[15-\{8+4\}]$

⇒ $\sf 28-[15-12]$

⇒ $\sf 28-3$

⇒ $\sf 25$

∴ $\sf 28-[15-\{8+20\div(7-(8-6))\}]=25$