Question

simplify this pleasee​

Answer 1

Answer:

2

Step-by-step explanation:

$2^{2n-1}$ × $4^{1-n}$

=> $2^{2n-1}$ × $2^{2(1-n)}$ [ Since 4 = 2²]

=>  $2^{2n-1}$ × $2^{2-2n}$

=> $2^{2n-1+2-2n}$

=> $2^{1}$

=> 2

Hope this helps

Have a nice day.