Question

simplify this problem ​

Answer 1

=4a²-12ab+9b²/2a-3b

=(2a)²-2(2a)(3b)+(3b)²/2a-3b

=(2a-3b)²/2a-3b

= (2a-3b)(2a-3b)/2a-3b

on cancellation

= 2a-3b will be the answer.

Hope it'll help you.

Answer 2

$\underline{\textbf{Question}}$
$\frac{4{a}^{2}}{2a-3b}-(\frac{12ab-{9b}^{2}}{2a-3b})$

$\underline{\textbf{Solution}}$

Now Sign will change Inside the bracket.
$\frac{ {4a}^{2} }{2a - 3b} \frac{ - 12ab + {9b}^{2} }{2a - 3b} \\ = \frac{ {4a }^{2} - 12ab + {9b}^{2} }{2a - 3b}$

According to (a-b)²=a²+b²-2ab
4a²=(2a)²
9b²=(3b)²
-12ab=2×3b×2a

Then Numerator=(2a-3b)²

Now Fraction
$\frac { \cancel{(2a-3b)} \times (2a-3b)}{\cancel{(2a-3b)}}$

$\boxed{\mathbf{Answer=2a-3b}}$