Question

Simplify this question

Answer 1

Answer:

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Answer 2

Answer:

$(\frac{a}{b} )^{4} \times (\frac{4ab}{3a} ) ^{2} \times ( \frac{b}{2a} ) ^{3} \\ = \frac{ {a}^{4} }{b^{4} } \times \frac{16a^{2} {b}^{2} }{ {9a}^{2} } \times \frac{ {b}^{3} }{ {8a}^{3} } \\ = \frac{16 {a}^{6} {b}^{5} }{72 {a}^{5} b ^{4} } \\ = \frac{2ab}{9}$