Question

simplify this question ​

Answer 1

Answer:

3√2/√3*(√2-1)+2√3/√2*

(√3+√3)4√3+√2*(√3-1)

=√6(√2-1+√6/(√3-1)2√6/√3-1

=√6(√2+1)√2²-1¹+√6(√3-√2)/√3²+√2²-2√6(√3+1)/√3²-1¹

=2√3+√6/2-1+3√2-2√3/1

2*(3√2+√(6)/2

=2√3-2√3+√6-√6+3√2-3√2

=0

Step-by-step explanation:

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