Math, asked by abhayrajput0001, 3 months ago

simplify.......
this question​

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Answered by manissaha129
2

Answer:

\huge \frac{ - 16 {( {x}^{2} \times y) }^{ - 3} }{ {x}^{3}  {y}^{2} }   \\\huge  =  \frac{ - 16 {x}^{ - 6} {y}^{ - 3}  }{ {x}^{3} {y}^{2}  }  =  \frac{ - 16}{ {x}^{9}  {y}^{5} }

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