Simplify using appropriate identity : (a + 3b) ^3 + (3a + b)^ 3
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(a+3b)³ + (3a+b)³
{Identity to use: (a+b)³ = a³ + 3a²b + 3ab² + b³ = a³ + 3ab(a+b) + b³}
Let us solve this question one by one.
Case 1:
(a+3b)³ by using the identity,
a³ + 3(a)(3b)(a+3b) + (3b)³
a³ + 9ab(a+3b) + 27b³
a³ + 9a²b + 27ab² + 27b³
Case 2:
(3a+b)³ by using identity,
(3a)³ + 3(3a)(b)(3a+b) + b³
27a³ + 9ab(3a+b) + b³
27a³ + 27a²b + 9ab + b³
Case 3:
add both of them:
a³ + 9a²b + 27ab² + 27b³ +27a³ + 27a²b + 9ab² + b³
by adding all the like terms,
28a³ + 36a²b + 36ab² + 28b³
28(a³+b³) + 36ab( a + b)
hope it helps
have a great day
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