Question

simplify using bodmas rule​

Answer 1

Step-by-step explanation:

=39/5÷(16/5-1/2(5/4-(5-4)/20))

=39/5÷(16/5-1/2(5/4-1/20))

=39/5÷(16/5-1/2((25-1)/20))

=39/5÷(16/5-1/2(24/20))

=39/5÷(16/5-3/5)

=39/5÷13/5

=39/5×5/13

=3

Answer 2

As the given question which have to simplify by using VBODMAS.

It menas we have to solve by bodmas rules which perform operation as first Viniculum, bracket, of, division,multiplication,addition and then subtraction.

Given that

$7 \frac{4}{5} \div (3 \frac{1}{5} - \frac{1}{2} (1 \frac{1}{4} - viniculum( \frac{1}{4} - \frac{1}{5} ))$

by solving viniculum

$7 \frac{4}{5} \div (3 \frac{1}{5} - \frac{1}{2} (1 \frac{1}{4} - \frac{1}{20} ))$

by solving mixed fraction we get

$\frac{39}{5} \div ( \frac{16}{5} - \frac{3}{5} )$

as base of fraction is same hence

$\frac{39}{5} \div ( \frac{16 - 3}{5} )$

$\frac{39}{5} \times \frac{5}{13}$

as by cancelling and division we get

$3$

hence Answer is 3.