simplify using identities:
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Step-by-step explanation:
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Answer:
(x - y)(x + y) + (y + z)(y - z) + (z - x)(z + x) = 0
Step-by-step explanation:
We have,
(x - y)(x + y) + (y + z)(y - z) + (z - x)(z + x)
Now,
we know that,
(a + b)(a - b) = a² - b²
Hence,
(x - y)(x + y) + (y + z)(y - z) + (z - x)(z + x)
= (x² - y²) + (y² - z²) + (z² - x²)
= x² - y² + y² - z² + z² - x²
= x² - x² + y² - y² + z² - z²
= 0
Hence,
(x - y)(x + y) + (y + z)(y - z) + (z - x)(z + x) = 0
Hope it helped and believing you understood it........All the best
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