Question

simplify using identity : (x+y) (x-y) +(y+z)(y-z) +(z+x)(z-x) ​

Answer 1

Answer:

hi there

Step-by-step explanation:

0 would be your required answer

Answer 2

$\mathcal{ \blue{ \large{ \boxed{Answer \: is \: 0}}}}$

Formula:-

$\mathcal { \boxed{ \purple{(a + b)(a - b) = ({a}^{2} - b {}^{2} )}}}$

$\sf{(x+y) (x-y) +(y+z)(y-z) +(z+x)(z-x) }$

$\sf{ = x {}^{2} - y {}^{2} + y {}^{2} - z {}^{2} + z {}^{2} - x {}^{2} }$

$\sf{ \orange{ \large{ = 0}}}$