Question

simplify using indices​

Answer 1

$\frac{( {27})^{3n + 1} \times (243) {}^{ \frac{ - 4n}{5} } }{(9) {}^{n + 5}(3) {}^{3n - 7} } = \frac{( ({3})^{3} ) {}^{3n + 1} ({3}^{5}) {}^{ \frac{ - 4n}{5} } }{ ({3}^{2}) {}^{n + 5} \times {3}^{3n - 7} } \\ \frac{(3 {})^{9n + 3}(3) {}^{ - 4n} }{ ({3})^{2n + 10} \times (3) {}^{3n - 7} } \\ \frac{(3) {}^{9n + 3 - 4n} }{(3) {}^{2n + 10 + (3n - 7)} } \\ \frac{(3 {)}^{5n + 3} }{(3) {}^{5n + 3} } = 1$

HAVE A NICE DAY!!!

HOPE IT HELPS YOU!!!

(ARMY)