Question

simplify using laws of exponents.
please with step by step explaination.
please answer quickly​

Answer 1

ANSWER:

To Simplify:

• (8^(x+1) × 8^3)/(8^(x+2))

Solution:

We are given that,

$\implies\dfrac{8^{x+1}\times8^3}{8^{x+2}}$

We know that,

$\hookrightarrow a^m\times a^n=a^{m+n}$

So,

$\implies\dfrac{8^{x+1}\times8^3}{8^{x+2}}$

$\implies\dfrac{8^{x+1+3}}{8^{x+2}}$

$\implies\dfrac{8^{x+4}}{8^{x+2}}$

We know that,

$\hookrightarrow \dfrac{a^m}{a^n}=a^{m-n}$

So,

$\implies\dfrac{8^{x+4}}{8^{x+2}}$

$\implies8^{x+4-(x+2)}$

$\implies8^{x+4-x-2}$

$\implies8^{2}$

$\implies8\times8$

$\implies\bf \dfrac{8^{x+1}\times8^3}{8^{x+2}}= 64$

Learn More:

$\begin{gathered}\boxed{\begin{minipage}{5 cm}\bf{\dag}\:\:\underline{\text{Laws of Exponents :}}\\\\\bigstar\:\:\sf\dfrac{a^m}{a^n} = a^{m - n}\\\\\bigstar\:\:\sf{(a^m)^n = a^{mn}}\\\\\bigstar\:\:\sf(a^m)(a^n) = a^{m + n}\\\\\bigstar\:\:\sf\dfrac{1}{a^n} = a^{-n}\\\\\bigstar\:\:\sf\sqrt[\sf n]{\sf a} = (a)^{\dfrac{1}{n}}\end{minipage}}\end{gathered}$

Answer 2

Answer:

REFER THE PHOTO UPLOADED

Step-by-step explanation: