Question

Simplify using properties:
6/7*49/18-7/3*1/49+6/7*1/18

Answer 1

your required answer is 47/21

hope it helps you mate

Answer 2

Answer:

$\frac{7}{3}$ is the required value of $\frac{6}{7}$ × $\frac{49}{18}$ - $\frac{7}{3}$ × $\frac{1}{49}$ + $\frac{6}{7}$ × $\frac{1}{18}$

Step-by-step explanation:

Explanation:

Given that, $\frac{6}{7}$ × $\frac{49}{18}$ - $\frac{7}{3}$ × $\frac{1}{49}$ + $\frac{6}{7}$ × $\frac{1}{18}$

• BODMAS rule - The Bodmas rule is arranged according to the letters in the acronym BODMAS, which stand for brackets, order of powers or roots, division, and multiplication, a stands for addition, and S for subtraction.

• According to the BODMAS rule, multi-operator mathematical equations must be resolved in the BODMAS order from left to right.

Step 1:

We have,  $\frac{6}{7}$ × $\frac{49}{18}$ - $\frac{7}{3}$ × $\frac{1}{49}$ + $\frac{6}{7}$ × $\frac{1}{18}$

First we simplify the multiplication part

⇒( $\frac{6}{7}$ × $\frac{49}{18}$ )-( $\frac{7}{3}$ × $\frac{1}{49}$ )+( $\frac{6}{7}$ × $\frac{1}{18}$) = $\frac{7}{3}$ - $\frac{1}{21}$ + $\frac{1}{21}$ = $\frac{7}{3}$

So, after calculation we get $\frac{7}{3}$.

Final answer:

Hence, $\frac{7}{3}$ is the required value of  $\frac{6}{7}$ × $\frac{49}{18}$ - $\frac{7}{3}$ × $\frac{1}{49}$ + $\frac{6}{7}$ × $\frac{1}{18}$.

#SPJ2