Simplify using suitable identities:
i) ( xy – yz )2 – 2xy2
z
ii) [ ( 2x + 3 ) ( 2x + 5 ) ] – 4x
iii) ( 5y – 2 ) ( 5y + 2 )
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Answer:
iii) ( 5y – 2 ) ( 5y + 2 )
((5y)²-2²)
25y²-4
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