Question

simplify using suitable identity.

Answer 1

$(ab)2 + (bc)2 + 2(ab )(bc) - 2ab2c \\ a2b2 + b2c2 - 2ab2c - 2ab2c \\ a2b2 + b2c 2$

Answer 2

$\bf\huge\color{red}\mathfrak{ hello\: mate!}$

$\bf\color{red}\mathfrak{Nice\: question !}$

$\color{blue}{ here's \:your \:answer!}$

(ab + bc)² - 2ab²c

= (ab)² + (bc)² + 2(ab)(bc) -2ab²c

= a²b² + b²c² + 2ab²c -2ab²c

= a²b² + b²c²

$\green{\boxed{\bold{\underline{ hope \: it \: is \: helpful}}}}$