simplify what is written in black and the last outer power is c^2-cb-b^2
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x^a/x^(-b) = x^(a+b)
then we get
(x^(a+b))^(a²-ab+b²)=x^((a+b)(a²-ab+b²))
(a+b)(a²-ab+b²)=a³-b³
so finally we get
x^(a³-b³)
similarlly we get x^(b³-c³),x^(c³-a³) for other two
on multiplying them we get
x^((a³-b³)+(b³-c³)+(c³-a³)) = x^(a³-a³+b³-b³+c³-c³)=x°=1
so final answer is 1
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