Question

simplify x^-1/2*2x^-1/2​

Answer 1

Answer:

$\dfrac{1}{\sqrt{2}x}$

Step-by-step explanation:

Given- [tex}[x^{-\dfrac{1}{2}] ×(2x)^{-\dfrac{1}{2}}[/tex]

= $x^{-\dfrac{1}{2}}] × [2^{-\dfrac{1}{2}}] × [x^{-\dfrac{1}{2}}$

We know- $a^{m}×a^{n} = a^{m+n}$

= $x^{-\dfrac{1}{2}-\dfrac{1}{2}} × 2^{-\dfrac{1}{2}}$

= $x^{-1} × (2)^{-\dfrac{1}{2}}$

= $\dfrac{1}{x} × \dfrac{1}{\sqrt{2}}$

= $\dfrac{1}{\sqrt{2}x}$