simplify x+1/x x-1/x x²+1/x² x⁴+1/x⁴
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Using the identity (a+b)(a-b) =a²- b² in all cases
[x+1/x][x-1/x][x²+1/x²][x*+1/x^] = [x²- 1/x²][x²+1/x²][xª+1/x^]
=[(x²)²- (1/x²)²][xª+1/x^]
=[x^-1/x^][x+1/x*]
=(x4)² - (1/x^)²
=x³-1/x8
hope it would be helpful
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