Question

simplify : √-x/16+√-x/25-√-x/36 where 'x' is positive real no.
​

Answer 1

$\textbf{To simplify:}$

$\sqrt{\dfrac{-x}{16}}+\sqrt{\dfrac{-x}{25}}+\sqrt{\dfrac{-x}{36}}$

$\textbf{Solution:}$

$\textbf{We know that the value of the imaginary unit \bf\,i=\sqrt{-1} }$

$\text{Consider,}$

$\sqrt{\dfrac{-x}{16}}+\sqrt{\dfrac{-x}{25}}+\sqrt{\dfrac{-x}{36}}$

$=\sqrt{\dfrac{x\,i^2}{16}}+\sqrt{\dfrac{x\,i^2}{25}}+\sqrt{\dfrac{x\,i^2}{36}}$

$=\dfrac{\sqrt{x}\,i}{4}+\dfrac{\sqrt{x}\,i}{5}+\dfrac{\sqrt{x}\,i}{6}$

$=\dfrac{15\sqrt{x}\,i+12\sqrt{x}\,i+10\sqrt{x}\,i}{60}$

$=\dfrac{37\sqrt{x}\,i}{60}$

$\therefore\bf\sqrt{\dfrac{-x}{16}}+\sqrt{\dfrac{-x}{25}}+\sqrt{\dfrac{-x}{36}}=\dfrac{37\sqrt{x}\,i}{60}$

Answer 2

Answer:

........ hope it helps