Question

simplify (x+2) (x+4)​

Answer 1

Answer:

$\sf{{x}^{2} + 6x + 8}$

Step-by-step explanation:

$\sf{(x + 2)(x + 4)}$

$\sf{by \: using \: the \: identity \: {\boxed{\sf(x + a)(x + b)}}}$

$\sf{and \: (x + a)(x + b) = {x}^{2} + (a + b) \times x + a \times b}$

$\sf{a = 2} \\ \sf{b = 4}$

$\sf{(x + 2)(x + 4) = {x}^{2} + (2 + 4) \times x + 2 \times 4}$

$\sf{= {x}^{2} + (6) \times x + 8}$

$\sf{ = {x}^{2} + 6x + 8}$

$\sf{\therefore \: the \: value \: of \: \boxed{\sf(x + 2)(x + 4) = {x}^{2} + 6x + 8}}$

$\bf{\pink{\underline{Be \: happy}}}$

Answer 2

Answer:

Answer:

\sf{{x}^{2} + 6x + 8}x

2

+6x+8

Step-by-step explanation:

\sf{(x + 2)(x + 4)}(x+2)(x+4)

\sf{by \: using \: the \: identity \: {\boxed{\sf(x + a)(x + b)}}}byusingtheidentity

(x+a)(x+b)

\sf{and \: (x + a)(x + b) = {x}^{2} + (a + b) \times x + a \times b}and(x+a)(x+b)=x

2

+(a+b)×x+a×b

\begin{gathered}\sf{a = 2} \\ \sf{b = 4}\end{gathered}

a=2

b=4

\sf{(x + 2)(x + 4) = {x}^{2} + (2 + 4) \times x + 2 \times 4}(x+2)(x+4)=x

2

+(2+4)×x+2×4

\sf{= {x}^{2} + (6) \times x + 8}=x

2

+(6)×x+8

\sf{ = {x}^{2} + 6x + 8}=x

2

+6x+8

Step-by-step explanation:

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