Simplify x(277-7x+3) and find the values of it for i)x=1 ii) x=0
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x(2x 2 −7x+3)
=x(2x 2 −6x−x+3)
=x[2x(x−3)−1(x−3)]
=x(2x−1)(x−3)
At x=0,the above expression equal to 0
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