Simplify x/2r2-7x+3) and find the values of it for (i)x= 1 and (ii)x=0
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0
x(2x
2
−7x+3)
=x(2x
2
−6x−x+3)
=x[2x(x−3)−1(x−3)]
=x(2x−1)(x−3)
At x=0,the above expression equals 0
Step-by-step explanation:
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