Math, asked by geethika4832, 5 hours ago

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Simplify x(2x? –7x+3) and find the values of it for (i)x=1 and (ii)x=0 who answer the question I make them as brainalist​

Answers

Answered by avnimaheshwari2000
0

Answer:

b = a ab = a² ab - b² = a²-b² b(a - b) = (a + b)(a - b) b= a + b b= b + b b= 2b 1= 2 where is the mistake there are 2 mistakes ?

Step-by-step explanation:

b = a ab = a² ab - b² = a²-b² b(a - b) = (a + b)(a - b) b= a + b b= b + b b= 2b 1= 2 where is the mistake there are 2 mistakes ?

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Answered by dipinderSingh
0

Step-by-step explanation:

x(2x 2−7x+3)

(2x 2−7x+3)=x(2x 2−6x−x+3)

(2x 2−7x+3)=x(2x 2−6x−x+3)=x[2x(x−3)−1(x−3)]

(2x 2−7x+3)=x(2x 2−6x−x+3)=x[2x(x−3)−1(x−3)]=x(2x−1)(x−3)

(2x 2−7x+3)=x(2x 2−6x−x+3)=x[2x(x−3)−1(x−3)]=x(2x−1)(x−3)At x=0,the above expression equals 0

(2x 2−7x+3)=x(2x 2−6x−x+3)=x[2x(x−3)−1(x−3)]=x(2x−1)(x−3)At x=0,the above expression equals 0

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