Question

Simplify x(2x² −7x+3) and find the values of it for
(i) x = 1 and (ii) x = 0

Answer 1

Step-by-step explanation:

$x( {2x}^{2} - 7x + 3) \\ {2x}^{3} - 7 {x}^{2} + 3x...........1 \\ put \: x = 1 \: in \: equation1 \\ 2 \times {1}^{3} - 7 \times {1}^{2} + 3 \times 1 \\ 2 - 7 + 3 = 2 \\ put \: x = 0 \: in \: equation \: no.1 \\ 2 \times {0}^{3} - 7 \times {0}^{2} + 3 \times 0 \\ 2 \times 0 - 7 \times 0 + 3 \times 0 \\ = 0$

Answer 2

Answer:

-2 and 0.

Step-by-step explanation:

To simplify the given equation x(2x² −7x+3) we have to factorize the equation within the bracket first which will be (2x² −7x+3) or (2x^2 -6x-x+3) or          (2x(x-3)-1(x-3)) which will be (2x-1)(x-3). So, multiplying with x will give that the value to be x(2x-1)(x-3).

The simplified form is (2x-1)(x-3)x so now putting the value of x=1 in the equation we will get that (2x-1)(x-3)x or (2*1-1)(1-3)1 = -2.

Again, on substituting the value of x as 0 we will get that, (2*0-1)(0-3)*0 to be entirely as 0.