Question

simplify:(x-3/x)(x^2+3+9/x^2)

Answer 1

Answer:

Expand (x−3)(x2+3x+9) ( x - 3 ) ( x 2 + 3 x + 9 ) by multiplying each term in the first expression by each term in the second expression.xx−3x2x2−9 x x - 3 x 2 x 2 - 9. Multiply the numerator by the reciprocal of the denominator. xx−3⋅x2−9x2 x x - 3 ⋅ x 2 - 9 x 2. Simplify terms. x(x+3)x−4. Explanation: factorise numerator and denominator. factor numerator. take out a common factor x. =x(x2−9). x2−9 is a difference of squares.

Step-by-step explanation:

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Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

${\bf{\green{=>(x-3/x)(x^2+3+9/x^2)}}}$

${\bf{\green{=>(x^2-3/x)(x^4+3x^2+9/x^2)}}}$

${\bf{\green{=>x^6+3x^4+9x^2-3x^4-9x^2-27/x^3}}}$

${\bf{\green{=>x^6+3x^4-3x^4+9x^2-9x^2-27/x^3}}}$

${\bf{\green{=>x^6/x^3-27/x^3}}}$

${\bf{\green{=>x^3-27/x^3}}}$