Math, asked by ursshiv, 6 months ago

simplify x^b-c/bc ×x^c-a/ca ×x^a-b/ab​

Answers

Answered by abhilashakumarijha18
2

Step-by-step explanation:

Hey friend,

Here is the answer you were looking for :

{x}^{a - b} \times {x}^{b - c} \times {x}^{c - a} = 1x

a−b

×x

b−c

×x

c−a

=1

We know that,

{a}^{m} \times {a}^{n} = {a}^{m + n}a

m

×a

n

=a

m+n

\begin{gathered}{x}^{a - b + b - c + c - a} = 1 \\ \\ {x}^{0} = 1 \\\end{gathered}

x

a−b+b−c+c−a

=1

x

0

=1

We know that anything with power 0 equals 1

1 = 11=1

Hence proved.

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

Answered by Yengalthilak12
3

 \frac{x {}^{b}  - c}{bc}  \times  \frac{ {x}^{c} - a }{ca}  \times  \frac{ {x}^{a}  - b}{ab}

 \frac{x {}^{b}c }{bc}  =  \frac{x \times b \times c}{b \times c}

 \:  \:  \:  \:  \:  \:  \:  = x

 \frac{ {x}^{c}a }{ca}  =  \frac{x \times c \times a}{c \times a}

 \:  \:  \:  \:  \:  \:  \:  = x

 \frac{ {x}^{a} b}{ab}  =  \frac{x \times a \times b}{a \times b}

 \:  \:  \:  \:  \:  \:  \:  = x

 \frac{ {x}^{b} - c }{bc}  \times  \frac{ {x}^{c}  - a}{ca}  \times  \frac{ {x}^{a} - b }{ab}  =

x \times x \times x = 3x

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