simplify X square + X - 2 into x square minus x + 2
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Solution:
Given (x²+x-2)(x²-x+2)
= [x²+(x-2)][x²-(x-2)]
= (x²)² - (x-2)²
/* (a+b)(a-b) = a²-b² */
= x⁴-(x²-2*x*2+2²)
= x⁴-(x²-4x+4)
= x⁴-x²+4x-4
Therefore,
(x²+x-2)(x²-x+2)
= x⁴-x²+4x-4
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